Kenita,
I'm finding this rather confusing. The confidence interval is for estimating a fixed population quantity such as a population mean. What quantity are you estimating? Are you just interested in whether last year's target + .5 falls in the CI for the 2012 mean? If so, a simple approach is to test the hypothesis that the 2012 mean is greater than last year's target + .5. Make sure your clients are not interpreting a CI or a hypothesis test for the population mean as a prediction interval for individual stores, which requires a different procedure.
Sometimes it sounds like you want to know if you need to increase the target by more than .5 to be sure of success, and that you believe stores can change their OSAT scores at will. This doesn't seem reasonable to me.
To estimate future means it helps to have data on change. Do you have multiple time points in your sample? If you had an estimate of the 2012 mean and an estimate of change or slope, you could get an estimate for the 2013 mean and test if it is greater than the old target + .5.
Good luck,
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William Stewart
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Original Message:
Sent: 03-08-2013 14:32
From: Kenita Hall
Subject: Confidence Intervals for Targets
This message has been cross posted to the following eGroups: Statistical Consulting Section and Statistics in Marketing Section .
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Hello,
Just to clarify my question...
I have data for 2012 but not for 2013 and we would like to tell the stores to increase their overall OSAT scores by .5 for 2013.
So, the question around the confidence level is: what would the target have to be in order to have 80% confidence that the growth has been at least 0.5?
1st attempt:
1) I found the confidence interval for the population mean from a random sample.
2) Increased each store's score by .5 then found the confidence interval for the population which is .5 above the original data
3) The 2013 "proposed" confidence interval overlaps with the 2012 confidence interval
I also tried to create bootstrap confidence intervals but my intervals still overlap.
How do I find the 2013 mean so that they don't overlap and the distance between the intervals is 0.5?
Thanks,
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Kenita Hall
Analytical Consultant
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